Math
posted by Amber .
The length of a rectangle is 5ft longer than twice the width. If the perimeter is 106ft, find the length and the width of the rectangle.

P = 2L + 2W
106 = 2(W + 5) + 2W
106 = 4W + 10
96 = 4W
24 = width 
What we know:
Length = 2X + 5
Width = X
Perimeter = 2L + 2W
106 = 2(2X + 5) + 2X
106 = 4X + 10 + 2X
106  10 = 6X
96 = 6X
96 = 6X
___ ___
6 6
16 = X
Now we know X is 16 (Width)
Let's substitute:
Width = 16
Length = 2X + 5
= 2(16) + 5
= 37
Double check answers:
Perimeter = 2L + 2W
106 = 2(37) + 2(16)
106 = 74 + 32