Posted by **Amber** on Tuesday, June 24, 2014 at 9:41pm.

The length of a rectangle is 5ft longer than twice the width. If the perimeter is 106ft, find the length and the width of the rectangle.

- Math -
**Ms. Sue**, Tuesday, June 24, 2014 at 9:49pm
P = 2L + 2W

106 = 2(W + 5) + 2W

106 = 4W + 10

96 = 4W

24 = width

- Math -
**John Paul**, Tuesday, January 12, 2016 at 10:12pm
What we know:

Length = 2X + 5

Width = X

Perimeter = 2L + 2W

106 = 2(2X + 5) + 2X

106 = 4X + 10 + 2X

106 - 10 = 6X

96 = 6X

96 = 6X

___ ___

6 6

16 = X

Now we know X is 16 (Width)

Let's substitute:

Width = 16

Length = 2X + 5

= 2(16) + 5

= 37

Double check answers:

Perimeter = 2L + 2W

106 = 2(37) + 2(16)

106 = 74 + 32

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