Calculate the atomic mass of naturally occurring molybdenum (Mo) which

contains the following isotopes.
Isotope Abundance (%) Atomic mass (a.u.)
92Mo 15.8 91.91
94Mo 9.0 93.90
95Mo 15.7 94.91
96Mo 16.5 95.91
97Mo 9.5 96.91
98Mo 23.5 97.91
100Mo 9.7 99.91

Too much typing. Do this

(%)(au) + (%)(au) + (%)(au) ........ = au
(0.158*91.91) + (0.009*93.90) + ..... = au.

To calculate the atomic mass of naturally occurring molybdenum (Mo), you need to multiply the abundance of each isotope by its atomic mass, and then sum up the results.

Step 1: Convert the percentages to decimal form.
- Divide each abundance percentage by 100 to convert it to decimal form.
- For example, the abundance of 92Mo is 15.8%, so you would write it as 0.158.

Step 2: Multiply the abundance of each isotope by its atomic mass.
- For example, multiply the abundance of 92Mo (0.158) by its atomic mass (91.91). The result is 0.158 * 91.91 = 14.49.

Step 3: Repeat step 2 for each isotope.

Isotope Abundance (%) Atomic mass (a.u.) (Abundance * Atomic mass)
92Mo 0.158 91.91 14.49
94Mo 0.090 93.90 8.45
95Mo 0.157 94.91 14.89
96Mo 0.165 95.91 15.83
97Mo 0.095 96.91 9.21
98Mo 0.235 97.91 23.04
100Mo 0.097 99.91 9.69

Step 4: Sum up the results from step 3.
- Add up all the values obtained from multiplying the abundance by atomic mass.
- Sum = 14.49 + 8.45 + 14.89 + 15.83 + 9.21 + 23.04 + 9.69 = 95.60

Therefore, the atomic mass of naturally occurring molybdenum (Mo) is approximately 95.60 atomic mass units (a.u).