John exerts constant force of 120 N for 10 s. on a stalled motorcycle. The final velocity is 8 m/s after the force was applied. If original velocity was zero, what is a)change of momentum b) the impulse produced c) magnitude of the mass of motorcycle
a&b) Impulse=deltaP=(120)(8)= 960
c.) how do I solve for magnitude of mass?
a) No
true a) the same as b)
but
impulse = F dt = delta (mv)
F dt = 120 N * 10 s = 1200 N s
The change of momentum is M (final velocity - 0)
so
1200 N s = M (8 m/s)
so
M = 150 N s^2/m
which is 150 kg
note
N force =Mass (m/s^2)
so
N s^2/m = M in kilograms
8 m =
Thanks for correcting me, I got the values wrong xD
lol Michel working on the same prob. as me.
To solve for the magnitude of the mass of the motorcycle, we can use the formula:
Impulse = Change in momentum = Force × Time
Since we have already calculated the impulse to be 960 N·s (as you mentioned in part b), we can substitute the values into the formula and solve for the magnitude of the mass.
Impulse = Force × Time
960 N·s = 120 N × 10 s
To solve for the magnitude of the mass, we can rearrange the equation:
Mass = Impulse / (Force × Time)
Mass = 960 N·s / (120 N × 10 s)
Simplifying the expression, we get:
Mass = 8 kg
Therefore, the magnitude of the mass of the motorcycle is 8 kg.