How many grams of hydrochloric acid should we use so we have exactly enough to react with 40g of sodium hydroxide? You'll need to write a chemical reaction, balance it, and then perform your calculation.

Dear Sally,

Here is the balanced equation
HCL(aq) + NAOH(aq)---- NACL(s)+ H20(l)

Number of moles in the NAOH(aq)=
40/(23+16+1)
=1
as 1 mole of HCL will react with 1 mole of the Naoh solution
number of mole of HCL required= 1

Still remember that there is a equation
mol= g/molar mass
Let the number of grams of HCL needed be g grams
the number of grams of HCL required=
1= g/(1+35.5)
g=36.5

Therefore, 36.5 grams of HCL is required
Hope it helps!!

To determine the amount of hydrochloric acid needed to react with 40g of sodium hydroxide, we first need to write and balance the chemical equation for the reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH):

HCl + NaOH → NaCl + H2O

Now, let's balance the equation:

HCl + NaOH → NaCl + H2O

The balanced equation is:

HCl + NaOH → NaCl + H2O

According to the balanced equation, 1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of NaCl and 1 mole of H2O.

To calculate the amount of HCl required, we need to convert the given mass of NaOH (40g) to moles. The molar mass of NaOH is 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.99 g/mol.

To convert grams of NaOH to moles, we use the following calculation:

Number of moles = Mass (g) / Molar mass (g/mol)

Number of moles of NaOH = 40g / 39.99 g/mol = 1.00 mol (approximately)

Since HCl and NaOH react in a 1:1 mole ratio, we need 1 mole of HCl to react completely with 1 mole of NaOH.

The molar mass of HCl is 1.01 g/mol + 35.45 g/mol = 36.46 g/mol.

Therefore, the mass of HCl needed can be calculated using the equation:

Mass of HCl (g) = Number of moles × Molar mass (g/mol)

Mass of HCl (g) = 1.00 mol × 36.46 g/mol = 36.46g

So, we would need approximately 36.46 grams of hydrochloric acid to react exactly with 40 grams of sodium hydroxide.