To find the velocity in the last two seconds, we need to first find the time it takes to arrive at the end of the street of 250 length, and assuming uniform acceleration.
The distance travelled is given by
Δx = vi(t)+(1/2)at²
vi=initial velocity (m/s)
Since the car started from rest, vi=0,
At t=2, Δx=20m
solving gives a=10 m/s²
Check at 4 sec.
Now we can assume uniform acceleration.
Calculate time to reach 250 m
So if we calculate where the car is located when t=√50 - 2, we have the distance travelled during the last two seconds, and can hence calculate the average velocity.
=(250-128.58)m /2 s
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