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March 1, 2015

March 1, 2015

Posted by **Piper** on Wednesday, June 18, 2014 at 8:38pm.

2. Two cyclist race with nearly uniform speed on a 500. m course. The blue bicycle crosses the finish line 2.00 s ahead of the red bicycle. If the red bicycle maintained an average speed of 10.0 m/s, what was the average speed of the blue bicycle?

- Physics -
**Henry**, Wednesday, June 18, 2014 at 9:52pm1. r1=d/t = 30m/5s = 6 m/s.=Speed of rabbit

r2=30m/120s = 0.25 m/s.=Speed of turtle

T1 = d/r1 = 96/6 = 16 s.=Rabbit's time.

T2 = d/r2 = 96/0.25 = 384 s. = Turtle's

time.

T2 - T1 = 384 - 16 = 368 s.

2. T2 = d/r2 = 500/10 = 50 s. = Time of

red bicycle.

d = r1 * T1 = 500

r1 = 500/T1 = 500/(50-2) = 10.42 m/s. =

Speed of blue bicycle.

- Physics -
**Piper**, Wednesday, June 18, 2014 at 10:04pmThank you

- Physics -
**Henry**, Thursday, June 19, 2014 at 7:24pmGlad I could help.

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