Posted by claire on Wednesday, June 18, 2014 at 7:50pm.
Limit as x approaches zero of (sinx(x^3/6)/x^5)

math please help  MathMate, Wednesday, June 18, 2014 at 10:21pm
I assume you forgot the parentheses in the numerator,
Lim (sin(x)(x^3/6))/x^5 as x>0
It would be easy to change sin(x) to a polynomial, the limits of which are easy to find.
If you expand sin(x) by Taylor's series, you'd get
sin(x)=xx³/6+x^5/120...
So the expression becomes
(x2x³/6+x^5/120x^7/5040+...)/x^5 as x>0
which gives +∞
However, if the question had been
Lim (sin(x)(xx³/6))/x^5, the result would be 1/120
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