If a latex balloon had a volume of 7.00 L at 39 °C, what would be the volume of this balloon at 21 °C?
(V1/T1) = (V2/T2)
Remember T must be in kelvin.
To find the volume of the balloon at 21 °C, we can use the combined gas law, which states that the ratio of the initial pressure, volume, and temperature of a gas to the final pressure, volume, and temperature of a gas is constant, as long as the amount of gas and the units of pressure are unchanged.
The formula for the combined gas law is:
(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂
where:
P₁ and P₂ are the initial and final pressures,
V₁ and V₂ are the initial and final volumes,
T₁ and T₂ are the initial and final temperatures.
In this case:
V₁ = 7.00 L (volume at 39 °C),
T₁ = 39 + 273.15 = 312.15 K (temperature in Kelvin at 39 °C),
T₂ = 21 + 273.15 = 294.15 K (temperature in Kelvin at 21 °C).
Now, let's rearrange the formula to solve for V₂:
(P₁ * V₁ * T₂) / (T₁ * P₂) = V₂
Since the question does not provide information about pressure, we can assume that the pressure is constant. Therefore, we can simplify the equation to:
V₂ = (V₁ * T₂) / T₁
Now substitute the given values into the equation:
V₂ = (7.00 L * 294.15 K) / 312.15 K
V₂ ≈ 6.597 L
Therefore, the volume of the balloon at 21 °C would be approximately 6.597 L.