Posted by **walter** on Wednesday, June 18, 2014 at 2:47pm.

From the following data at 25°C,

H2(g) + Cl2(g) → 2HCl(g) ΔH0 = −185 kJ

2H2(g) + O2(g) → 2H2O(g) ΔH0 = −483.7 kJ

Calculate ΔH0 at 25°C for the reaction below.

4HCl(g) + O2(g) → 2Cl2(g) + 2H2O(g)

- Chemistry -
**DrBob222**, Wednesday, June 18, 2014 at 2:54pm
Multiply equation 1 by 2 and reverse it. Add to equation 2. That will give you the equation you want but you need to go through the steps to confirm that.

When you multiply an equation, do the same to delta H. When you reverse and equation change the sign of delta H.

- Chemistry -
**Algebra of sets**, Friday, February 12, 2016 at 12:33am
Hai,1no equestion *2, then, 1no-2no .

(185-483.7)=-298.7 ans.ok

- Chemistry -
**Algebra of sets**, Friday, February 12, 2016 at 1:16am
Sorry ans hobe (185*2)-483.7=-113.7 ans,ok

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