A gas occupies 210 mL at -73°C. To have the same gas occupy 360 mL:

Should the temperature be increased or decreased?

What is the new temperature?
A)120 K
B)0.0029 K
C)340 K

(V1/T1) = (V2/T2)

Remember T must be in kelvin.
(210/200) = (360/T2)
Solve for T2 in K

INCREASE

Well, to make the gas occupy a larger volume, we need to increase the temperature. As for the specific new temperature, let me do some clown calculations for you. 🤡

Given that the initial temperature is -73°C, which is approximately 200 K, we need to increase it to 360 mL. Now, we can use the combined gas law equation to find the new temperature:

(P₁V₁/T₁) = (P₂V₂/T₂)

Since the pressure remains constant, we can rewrite it as:

(V₁/T₁) = (V₂/T₂)

Plugging in the values we have, we get:

(210 mL/200 K) = (360 mL/T₂)

Cross-multiplying and solving for T₂, we find:

T₂ = (360 mL x 200 K) / 210 mL

Doing some clown calculations, we get:

T₂ ≈ 342.857 K

So, the new temperature should be approximately 342.857 K, which is not among the options you provided. Looks like this is one clown question! 🤡

To determine whether the temperature should be increased or decreased, we need to consider the relationship between volume and temperature, known as Charles' Law. According to Charles' Law, the volume of a gas is directly proportional to its temperature, given that pressure and amount of gas remain constant.

In this case, we have a fixed amount of gas at a different volume and temperature. The initial volume is 210 mL, and we want the gas to occupy 360 mL. Since we are increasing the volume, we need to increase the temperature as well.

To find the new temperature, we can use the formula:

(V1/T1) = (V2/T2)

Substituting the given values, we have:

(210 mL / -73°C) = (360 mL / T2)

Now we can solve for T2:

T2 = (360 mL * -73°C) / 210 mL

T2 ≈ -124.57°C

The new temperature is approximately -124.57°C. However, the answer choices are provided in Kelvin (K). To convert from Celsius (°C) to Kelvin (K), we use the formula:

K = °C + 273.15

Converting the temperature to Kelvin gives:

T2 ≈ -124.57°C + 273.15

T2 ≈ 148.58 K

Among the provided answer choices, the new temperature is approximately 148.58 K. Therefore, option C) 340 K is incorrect, and the correct answer is A) 120 K.

The answer is 340 because the temperature should be increased and that is the only option that is above the original number of 210