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A gas occupies 210 mL at -73°C. To have the same gas occupy 360 mL:

Should the temperature be increased or decreased?

What is the new temperature?
A)120 K
B)0.0029 K
C)340 K

  • chemistry -

    (V1/T1) = (V2/T2)
    Remember T must be in kelvin.
    (210/200) = (360/T2)
    Solve for T2 in K

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