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December 20, 2014

December 20, 2014

Posted by **tanvir** on Wednesday, June 18, 2014 at 7:22am.

(i) 1/1+√2+√3

- math -
**Steve**, Wednesday, June 18, 2014 at 11:44am1/(1+√2+√3) * 1/(1-(√2+√3))/(1-(√2+√3))

= (1-√2-√3)/(1 - (√2+√3)^2)

= (1-√2-√3)/(-4-2√6)

= (1-√2-√3)/(-2(2+√6))

= (1-√2-√3)/(-2(2+√6)) * (2-√6)/(2-√6)

= (1-√2-√3)(2-√6)/-2 * 1/(4-6)

= (2+√2-√6)/4

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