a sample of ammonium phosphate (NH4)3PO4 contains 3.18 mole of H atoms. number of mole of o atoms in the sample is:

mols (NH4)3PO4 = 3.18 mols H x (1 mol (NH4)3PO4/12 mols H) = ?

Then mols O is 4x that since there are 4 atoms O in 1 molecule (NH4)3PO4

47.2

4B

To find the number of moles of oxygen (O) atoms in a sample of ammonium phosphate ((NH4)3PO4) knowing the number of moles of hydrogen (H) atoms, you need to consider the balanced chemical formula of ammonium phosphate.

The formula for ammonium phosphate is (NH4)3PO4. From the formula, you can deduce that each molecule of ammonium phosphate contains four oxygen atoms (O). Therefore, in one mole of ammonium phosphate, there are four moles of oxygen atoms.

Since you have the number of moles of hydrogen atoms (H), and each molecule of ammonium phosphate contains 12 moles of hydrogen atoms (4 from the (NH4) group and 8 from the H2O group), you can use the stoichiometry to find the number of moles of oxygen atoms.

The stoichiometric ratio between hydrogen (H) and oxygen (O) atoms in ammonium phosphate is 12:4. This means that for every 12 moles of hydrogen atoms, there are 4 moles of oxygen atoms.

Given that you have 3.18 moles of hydrogen atoms, you can set up a ratio and solve for the number of moles of oxygen atoms.

(3.18 moles H) x (4 moles O/12 moles H) = 1.06 moles O

Therefore, there are approximately 1.06 moles of oxygen atoms in the sample of ammonium phosphate.