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March 31, 2015

March 31, 2015

Posted by **Nihira** on Tuesday, June 17, 2014 at 11:21pm.

csc^2x = 2sec2x / sec2x - 1

Sorry i really tried. I got : LS = 1 - (cos^2x/sin^2x) but thats it. please help

- Math -
**Steve**, Wednesday, June 18, 2014 at 5:26ammultiply RS top and bottom by cos2x and you have

2/(1-cos2x)

= 2/(1-(cos^2 x - sin^2 x))

= 2/(1-cos^2 x + sin^2x)

= 2/(2sin^2 x)

= 1/sin^2 x

= csc^2 x

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