Posted by **Anonymous** on Tuesday, June 17, 2014 at 9:55pm.

Use back substitution to solve the system of linear equations

x-2y+z=8

y+z=5

z=2

**I tried to solve it eventho im still confused/lost.

1=3 idk ugh

- Math -
**Reiny**, Tuesday, June 17, 2014 at 10:07pm
well, let's put z=2 into the 2nd

z=y + 2 = 5

y = 3

So now we know that z=2 and y = 3

now into the 1st:

x - 6 + 2 = 8

z = 12

So, where was your problem with this ?

Looks very very easy.

- Math -
**Anonymous**, Tuesday, June 17, 2014 at 10:11pm
Thanks ...its easy for you because your good in math. IM not.

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