Posted by Anonymous on Tuesday, June 17, 2014 at 9:55pm.
Use back substitution to solve the system of linear equations
x2y+z=8
y+z=5
z=2
**I tried to solve it eventho im still confused/lost.
1=3 idk ugh

Math  Reiny, Tuesday, June 17, 2014 at 10:07pm
well, let's put z=2 into the 2nd
z=y + 2 = 5
y = 3
So now we know that z=2 and y = 3
now into the 1st:
x  6 + 2 = 8
z = 12
So, where was your problem with this ?
Looks very very easy.

Math  Anonymous, Tuesday, June 17, 2014 at 10:11pm
Thanks ...its easy for you because your good in math. IM not.
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