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Use back substitution to solve the system of linear equations

**I tried to solve it eventho im still confused/lost.
1=3 idk ugh

  • Math -

    well, let's put z=2 into the 2nd

    z=y + 2 = 5
    y = 3
    So now we know that z=2 and y = 3

    now into the 1st:
    x - 6 + 2 = 8
    z = 12

    So, where was your problem with this ?
    Looks very very easy.

  • Math -

    Thanks ...its easy for you because your good in math. IM not.

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