Posted by sunny on Tuesday, June 17, 2014 at 7:00pm.
what is the vertex of y=x^24 ??

math  Damon, Tuesday, June 17, 2014 at 7:23pm
x^2  4 = y
x^2  4 + (4/2)^2 = y + (4/2)^2
(x2)^2 = y + 4
so
vertex at (2,4)
Posted by sunny on Tuesday, June 17, 2014 at 7:00pm.
what is the vertex of y=x^24 ??
x^2  4 = y
x^2  4 + (4/2)^2 = y + (4/2)^2
(x2)^2 = y + 4
so
vertex at (2,4)