The sum of two angles of a triangle is 116 degree and their differences is 24 degree.Find the measure of each angle of the triangle.

Let the angle ne x and y .

If we take x+y=116°....(1)
x-y=24°.....(2)
We know that the sum of an angle of an ∆ is 180°
So, x+y= 116°
x=(180-116)°
X=64°
Now , on adding (1)..(2)
We get, 2x=140
=>140/2
=>70°
Simply sum of am angle of an ∆ is 180°. So, another angle is 46°.

One angle is 70 , another is 46°, and third angle is 65°

let the angles be x and y

x+y = 116
x-y = 24
add them
2x = 140
x = 70
then y = 46

one angle is 70°, the other is 46° leaving 64° for the third angle

Science

To find the measure of each angle of the triangle, we can set up a system of equations based on the given information.

Let's denote the two angles as A and B, with A being the bigger angle. We are given that:

A + B = 116 (Equation 1)
A - B = 24 (Equation 2)

Now, we can solve this system of equations to find the values of A and B.

To do this, we can use the method of elimination. Add Equation 1 and Equation 2 together:

(A + B) + (A - B) = 116 + 24

Simplifying the equation, we get:

2A = 140

Now, divide both sides by 2 to solve for A:

A = 70

Substitute this value of A back into either Equation 1 or Equation 2. Let's use Equation 1:

70 + B = 116

Now, subtract 70 from both sides to solve for B:

B = 116 - 70

B = 46

So, the measure of angle A is 70 degrees and the measure of angle B is 46 degrees.