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March 5, 2015

March 5, 2015

Posted by **tanaiah** on Monday, June 16, 2014 at 11:28pm.

- projectile motion -
**Steve**, Tuesday, June 17, 2014 at 12:05amwe know that the path follows

x(t) = v cosθ t

y(t) = 160 + v sinθ t - 4.9t^2

I will assume that the cliff and the tower are the same, otherwise I'm confused.

x(20) = 1800

y(20) = 0

So,

20v cosθ = 1800

20v sinθ = 1800

Clearly θ = π/4 and v = 127.28 m/s

y = 160 + 90t - 4.9t^2

so at t=9.18 the max height of 573.27m is attained.

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