Wednesday

December 17, 2014

December 17, 2014

Posted by **Kyle** on Monday, June 16, 2014 at 10:07pm.

interval of 4.08 seconds.

(a.) What is the average acceleration of the car during this time?

(b.) Assuming the acceleration is constant, how far did the car travel during this time?

- General Physics 1 -
**Damon**, Monday, June 16, 2014 at 10:23pmchange in velocity/ change in time = (17.9-29.6) / 4.08

= -2.67 m/s^2

d = Vi t - (1/2) 2.67 * t^2

= 29.6(4.08) - 1.33 (4.08^2)

= 121 - 22.1

= 98.9 m

**Answer this Question**

**Related Questions**

physics - In this problem you will determine the average velocity of a moving ...

physics - A car is moving with constant velocity. Which of the following is true...

physics - An object moves with constant acceleration 3.65 m/s2 and over a time ...

AP Calculus - The position of a particle moving on the x-axis at time t>0 ...

Physics - An object moves with constant acceleration 4.95 m/s2 and over a time ...

College Physics - An object moves with constant acceleration 4.95 m/s2 and over ...

Calculus III - A particle is moving in R2 according to the law x=t^2, y=t^3 (...

Calculus - The displacement (in meters) of a particle moving in a straight line ...

physics - A car is traveling along a straight road at a velocity of +32.7 m/s ...

Physics - A car traveling with an initial velocity of 15.5 m/s accelerates at a ...