Two Kids pull opposite directions on a toy with a mass of 18kg. One exerts a force of 695N and the other 135N. Both pull horizontally and friction is void. Calculate the new force in N?

695 - 135 = 560 N

that is the answer you asked for
If you also want the acceleration it is
a = F/m = 560/18 = 31.1 m/s^2

To calculate the net force, we need to subtract the force exerted in one direction from the force exerted in the opposite direction.

Let's denote F1 as the force exerted by the first child (695N) and F2 as the force exerted by the second child (135N).

Since the forces are applied in opposite directions, we can subtract the smaller force from the larger force:

Net force = |F1 - F2|

Therefore, the net force exerted on the toy is:

Net force = |695N - 135N|
= |560N|
= 560N

Hence, the new force exerted on the toy is 560 Newtons.