Posted by Anonymous on .
A 5kg crate falls from height of 2 m into an industrial spring scale. When the crate comes to rest the compression of the spring is 25 cm what is the spring constant?
loss of gravitational potential energy
= m g * change in height
= 5 * 9.81 *(2 + .25)
= 110 Joules
that is now stored in the spring (1/2)kx^2
(1/2) k (.25)^2 = 110
k = 3532 N/m