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Determine the mass of carbon dioxide that will be formed when 131.0 g of propane (C3H8) is reacted with 32 g of oxygen (O2)

C3H8 + 5O2 --> 3CO2 + 4H2O

I got O2 as my limiting reagent. Then I used the mol of that which is 1 mol to find the mol of CO2 which I got as 0.6 mol. My final answer is 26.4 g of CO2 but the answer sheet says something else. Am I right?

  • Chemistry -

    I think you can take your answer to the bank.

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