If h is 5m and the mass takes 3 s to move the distance d when starting from rest, what is the distance d? PLEASEEEEEE!!!!
To find the distance, d, we need to use the equation of motion:
d = (1/2) * g * t^2
where d is the distance, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time taken.
From the given information, we know that the height, h, is 5m and the time taken, t, is 3s.
Firstly, we need to find the time it takes for an object to fall from height h using the formula:
h = (1/2) * g * t^2
Rearranging the formula to solve for t:
t^2 = (2 * h) / g
Substituting the given values:
t^2 = (2 * 5) / 9.8
t^2 ≈ 1.02
Taking the square root of both sides:
t ≈ √1.02
t ≈ 1.01 s
Now that we have the correct time, we can calculate the distance, d, by substituting the time value into the equation:
d = (1/2) * g * t^2
Substituting the values:
d = (1/2) * 9.8 * (1.01^2)
d ≈ 4.95 m
Therefore, the distance, d, approximately equals 4.95 meters.