Determine the concentration of iron in an aqueous solution containing 0.2810 grams of Fe(NH4)2(SO4)2 per liter of solution. Express the concentration in mg/dl.

I am sorry. I meant mg/L

0.2810g Fe(NH4)2(SO4)2 x (1000 mg/g) x [1 mol Fe/1 mol Fe(NH4)2(SO4)2] x (1 mol Fe(NH4)2(SO4)2/284g) x (55.85g Fe/1 mol Fe) = ?

Or without all the mishmash it is
0.2810 x (atomic mass Fe/molar mass Fe(NH4)2(SO4)2) x 1000 = 0.2810 x (55.85/284) x 1000 = ?

Thank you DrBob222! You saved my day.

To determine the concentration of iron in the solution, we need to calculate the number of moles of iron present and then convert it to the desired unit, mg/dl.

1. Calculate the molar mass of Fe(NH4)2(SO4)2:
Fe: 55.845 g/mol
N: 14.007 g/mol (x2, since there are two NH4 groups)
H: 1.008 g/mol (x8, two from each NH4 group)
S: 32.06 g/mol (x2, since there are two SO4 groups)
O: 16.00 g/mol (x8, four from each SO4 group)

Molar mass of Fe(NH4)2(SO4)2:
= (55.845) + (14.007 x 2) + (1.008 x 8) + (32.06 x 2) + (16.00 x 8)
= 392.174 g/mol

2. Convert the mass of Fe(NH4)2(SO4)2 to moles:
Mass of Fe(NH4)2(SO4)2 = 0.2810 grams
Moles of Fe(NH4)2(SO4)2 = 0.2810 grams / 392.174 g/mol

3. Calculate the concentration of Fe in moles per liter (mol/L) by dividing the number of moles of Fe(NH4)2(SO4)2 by the volume of the solution (1 liter):
Concentration of Fe = (0.2810 g / 392.174 g/mol) / 1 L

4. Convert the concentration to mg/dl. To do this, we need to consider the conversion factors:
1 g = 1000 mg
1 L = 1000 dl

Concentration of Fe in mg/dl = (Concentration of Fe in mol/L) x (1000 mg/g) x (1000 dl/L)

By following these steps, you can calculate the concentration of iron in the given aqueous solution in mg/dl.