calculate the percentage by mass of ozygen in trioxnitrate5 acid H-1, N-14, O-16

HNO3.

mass HNO3 = 1+14+(3*16) = about 63.
mass O = 3*6 = 48
%O = (mass O/mass HNO3)*100 = ?

Replace mass O = 3*6= 18

with mass O = 3*16 = 48

To calculate the percentage by mass of oxygen in trioxinitrate5 acid (HNO3), we need to determine the molar masses of each element present and use them to calculate the mass of oxygen in the compound.

Here are the atomic masses for hydrogen (H), nitrogen (N), and oxygen (O):

H: 1 g/mol
N: 14 g/mol
O: 16 g/mol

The molecular formula of trioxinitrate5 acid (HNO3) indicates that it contains one hydrogen atom, one nitrogen atom, and three oxygen atoms.

To calculate the molar mass of HNO3, we multiply the atomic masses by their respective subscripts in the formula and sum them up.

Molar mass of HNO3 = (1 * 1) + (1 * 14) + (3 * 16)
= 1 + 14 + 48
= 63 g/mol

Next, we find the mass contribution of oxygen in HNO3.

Mass of oxygen = (3 * 16)
= 48 g/mol

Now that we know the mass of oxygen in HNO3 is 48 g, we can calculate its percentage by mass.

Percentage by mass of oxygen = (mass of oxygen / total molar mass of HNO3) * 100
= (48 / 63) * 100
≈ 76.19%

Therefore, the percentage by mass of oxygen in trioxinitrate5 acid (HNO3) is approximately 76.19%.