How would i solve this?
A 10.0 kg ball falling at 10.0 m/s hits a pile of feathers and comes to a complete stop in 10 s. What force does the pile of feathers exert to stop the ball?
10 N
20 N
100 N
200 N
Force * time = impulse = change in momentum
T (10) = 10 * 10
T = 10 N
which by the way is about the weight of the ball on earth. I think it would take longer.
thank you
You are welcome.
wait a minute, add the weight of the ball!.
10 + 10*9.81 = 108 N
oh okay, thanks Damon :)
To solve this problem, we can use Newton's Second Law of Motion, which states that the force exerted on an object is equal to the mass of the object multiplied by its acceleration. In this case, since the ball comes to a complete stop, its final velocity is 0 m/s, and the time taken to stop is 10 s.
First, we need to calculate the deceleration of the ball. We can use the equation:
Final velocity = Initial velocity + (acceleration x time)
Since the final velocity is 0 m/s, the equation becomes:
0 m/s = 10 m/s + (acceleration x 10 s)
Solving for acceleration:
acceleration x 10 s = -10 m/s
acceleration = -1 m/s²
The negative sign indicates that the ball is decelerating.
Next, we can calculate the force exerted on the ball by the feathers using Newton's Second Law. The formula is:
Force = mass x acceleration
Force = 10 kg x (-1 m/s²)
Force = -10 N
The negative sign indicates that the force is in the opposite direction of motion. However, since the question is asking for the magnitude of the force, we ignore the negative sign and take the absolute value.
Therefore, the pile of feathers exerts a force of 10 N to stop the ball.
The correct answer is: 10 N.