monkey is accelerating down string whose breaking strength is two third of its weight the min acceleration of monkey should be A 1/3g B 2/3g C G d ZERO
Net force on monkey:
Fnet = weight - tension = mg - T
Newton's 2nd Law:
mg - T = ma
Solve for "T":
T = m(g-a)
To avoid breaking, T can be no more than 2/3 of monkey's weight:
T ≤ (2/3)mg
Substitute "m(g-a)" for T:
m(g-a) ≤ (2/3)mg
Solve this inequality for "a":
a ≥ (1/3)g
Good
let the weight of monkey is mg then maximum tension in rope be 2 mg/3 now using Newton 2nd law mg_T =ma mg_2/3mg=ma 1/3 mg=ma 1/3g=a
To find the minimum acceleration of the monkey, we need to consider the tension in the string.
First, let's assume the weight of the monkey is W. According to the problem, the breaking strength of the string is two-thirds of the weight, which means the maximum tension the string can withstand is (2/3)W.
Now, let's analyze the forces acting on the monkey. We have the weight force acting downward, which is W, and the tension force acting upward in the string.
Since the monkey is accelerating down the string, the net force acting on it must be downward. Therefore, the tension force in the string (which is acting upward) must be less than the weight force (which is acting downward).
In other words, the tension force in the string must be less than W for the monkey to accelerate downward.
So, the maximum tension force the string can withstand is (2/3)W, and for the monkey to accelerate downward, the tension force must be less than W.
The minimum acceleration of the monkey will occur when the tension force is equal to W, because any greater tension force would prevent the monkey from accelerating downward.
Therefore, the minimum acceleration of the monkey should be option C: G (acceleration due to gravity).