I am a five-digit number greater than 60,000 but less than 70,000. My ones is 1 less than my ten thousands digit. All my other are the same. the sum of my digits is 23. what is my number?

6x,xx5

so
11 + 3 x = 23
3 x = 12
x = 4
64,445

23

23

I am a five digit number greater than 60,000 but less than 70,000.my ones digit is 1less than my ten thousands digit.all my other digits was the same.the sum of my digits is 23.what am I

To find the five-digit number that satisfies the given conditions, we can break down the problem step by step:

Step 1: Start with the given information.
- The number is greater than 60,000 but less than 70,000.
- The ones digit is 1 less than the ten thousands digit.
- The sum of the digits is 23.

Step 2: Determine the range of possible values for the ten thousands digit.
- Since the number is greater than 60,000 and less than 70,000, the ten thousands digit can only be 6. From 60,000 to 69,999, the ten thousands digit is always 6.

Step 3: Calculate the sum of the remaining four digits.
- The sum of all five digits is 23. We know the ten thousands digit is 6, so we need to find four more digits that sum up to 23 - 6 = 17.

Step 4: Determine the possible values for the ones digit.
- The ones digit is 1 less than the ten thousands digit, which is 6. Therefore, the ones digit can be 5.

Step 5: Distribute the remaining sum among the three remaining digits.
- We now have three digits remaining since we already have the ten thousands digit and the ones digit. These three digits need to sum up to 17 - (6 + 5) = 6.

Step 6: Find the values for the remaining three digits.
- We need to find three digits that sum up to 6. The only possible combination is 2 + 2 + 2 = 6.

Step 7: Combine all the digits to get the final number.
- The final number is 62,222.

Therefore, the five-digit number that satisfies the given conditions is 62,222.