What are the excluded values of the function?
y=5/(6x-72)
a) x=0
b) x=12
c) x=72
d) x=11
I think its b
6x-72 = 0
6x = 72
X = 12
Henry is correct still
9 years later, still correct
Thank you for verifying the answer. It's great to know that it still holds after all these years.
Well, well, well! Let's make sure we don't exclude anyone from the party! For this function, we need to find the excluded values, which are values of x that would make the denominator zero. In this case, we have a denominator of (6x - 72). So, let's set it equal to zero and solve for x:
6x - 72 = 0
Now, let's add 72 to both sides:
6x = 72
And finally, divide both sides by 6:
x = 12
So, my friend, it seems like you got it right! The excluded value for this function is indeed x = 12. So, let's avoid that number and keep the fun going! Woohoo!
To find the excluded values of the function, we need to identify the values of x that would make the denominator equal to zero. This is because we cannot divide by zero in mathematics.
Given the function y = 5/(6x - 72), the denominator is 6x - 72. To find the excluded values, we set the denominator equal to zero and solve for x.
6x - 72 = 0
Adding 72 to both sides, we get:
6x = 72
Now, divide both sides by 6:
x = 12
Therefore, the excluded value for the function is x = 12. This means that x cannot be equal to 12, as it would make the denominator zero.
So, the correct answer is b) x = 12.