An electron, travelling at 2000 m/s, is suddenly influenced by an extreme deceleration of 3000 m/s2. How fast is it going 0.03 s later?

V = Vo + a*t = 2000 + (-3000)*0.03 =

1910 m/s.

To calculate the final velocity of the electron, we can use the equation of motion:

v = u + at

Where:
v = final velocity
u = initial velocity
a = acceleration
t = time

Given:
Initial velocity, u = 2000 m/s (positive because it's traveling)
Acceleration, a = -3000 m/s² (negative because it's decelerating)
Time, t = 0.03 s

Now, let's substitute the values into the equation and solve for the final velocity:

v = 2000 m/s + (-3000 m/s²) × 0.03 s

First, let's calculate the term (-3000 m/s²) × 0.03 s:

(-3000 m/s²) × (0.03 s) = -90 m/s

Now we can substitute it back into the equation:

v = 2000 m/s + (-90 m/s)
v = 1910 m/s

Therefore, the electron will be traveling at a speed of 1910 m/s 0.03 seconds later after experiencing an extreme deceleration of 3000 m/s².