An electron, travelling at 2000 m/s, is suddenly influenced by an extreme deceleration of 3000 m/s2. How fast is it going 0.03 s later?
V = Vo + a*t = 2000 + (-3000)*0.03 =
1910 m/s.
To calculate the final velocity of the electron, we can use the equation of motion:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
Given:
Initial velocity, u = 2000 m/s (positive because it's traveling)
Acceleration, a = -3000 m/s² (negative because it's decelerating)
Time, t = 0.03 s
Now, let's substitute the values into the equation and solve for the final velocity:
v = 2000 m/s + (-3000 m/s²) × 0.03 s
First, let's calculate the term (-3000 m/s²) × 0.03 s:
(-3000 m/s²) × (0.03 s) = -90 m/s
Now we can substitute it back into the equation:
v = 2000 m/s + (-90 m/s)
v = 1910 m/s
Therefore, the electron will be traveling at a speed of 1910 m/s 0.03 seconds later after experiencing an extreme deceleration of 3000 m/s².