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February 28, 2015

February 28, 2015

Posted by **Anonymous** on Wednesday, June 11, 2014 at 1:36pm.

- physics -
**Damon**, Wednesday, June 11, 2014 at 1:47pmDo the vertical problem first

Vi = initial speed up

then

v = Vi - g t

at top, v = 0

0 = Vi - g t

Vi = g t

t = Vi/g

h = 0 + Vi t - .5 g t^2

14 = Vi^2/g - .5 Vi^2/g

28 g = Vi^2

Vi = sqrt (28 g)

Vi = 16.6 m/s

Vi = v sin theta

16.6 = 24 sin theta

so ....

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