10. You have six $1 bills, eight $5 bills, two $10 bills , and four $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then $10)?

A. 77/190
B. 3/100
C. 3/95*****?
D. 2/5

prob = (6/20)(2/19)

= 3/95

you were right

To find the probability of selecting a $1 bill followed by a $10 bill without replacement, we need to calculate the number of favorable outcomes and the total number of possible outcomes.

First, let's determine the total number of bills in your wallet:
Total number of bills = 6 (number of $1 bills) + 8 (number of $5 bills) + 2 (number of $10 bills) + 4 (number of $20 bills) = 20

Now, let's calculate the number of favorable outcomes, which is the number of ways we can select a $1 bill followed by a $10 bill:
Number of ways to select a $1 bill = 6 (since there are 6 $1 bills)
Number of ways to select a $10 bill = 2 (since there are 2 $10 bills)

Since we are choosing without replacement, once we select a $1 bill, we have one less bill in the wallet.

Therefore, the number of favorable outcomes = 6 (number of ways to select a $1 bill) * 2 (number of ways to select a $10 bill) = 12

Finally, we can calculate the probability using the formula:
P($1, then $10) = Number of favorable outcomes / Total number of possible outcomes
P($1, then $10) = 12 / 20 = 3/5

So, the correct answer is D. 2/5

To find the probability of selecting a $1 bill followed by a $10 bill without replacement, we need to calculate the following:

P($1, then $10) = (Number of ways to choose a $1 bill) * (Number of ways to choose a $10 bill) / (Total number of ways to choose two bills without replacement)

1. The number of ways to choose a $1 bill is 6, as there are six $1 bills in your wallet.

2. The number of ways to choose a $10 bill is 2, as there are two $10 bills in your wallet.

3. The total number of ways to choose two bills without replacement can be calculated as the number of ways to choose any two bills from the total number of bills in the wallet, which is:

Total number of ways = (Number of ways to choose the first bill) * (Number of ways to choose the second bill)

Number of ways to choose the first bill = Total number of bills = 6 + 8 + 2 + 4 = 20

Number of ways to choose the second bill = Total number of bills - 1, since we are not replacing the first bill = 20 - 1 = 19

Therefore, the total number of ways to choose two bills without replacement is:

Total number of ways = 20 * 19 = 380

Now let's substitute these values to calculate the probability:

P($1, then $10) = (Number of ways to choose a $1 bill) * (Number of ways to choose a $10 bill) / (Total number of ways to choose two bills without replacement)

P($1, then $10) = (6 * 2) / 380

P($1, then $10) = 12 / 380

Simplifying the fraction, we get:

P($1, then $10) = 3 / 95

Therefore, the correct answer is C. 3/95.