Help please
A wire carries a current of 5.2 A from east to west through a 6.0 m section of wire in the earth's magnetic field of 1 × 10^-5 T at a location where the magnetic field points south. What is the magnitude of the magnetic force acting on the wire?
3.1 × 10^-4 N
3.1 N
5.2 × 10^-5 N
6.0 × 10^-5 N
nvm i got this one, i think
5.2*6.0*.0001
.000312=
3.1*10^-4 N
so is this A?
To find the magnitude of the magnetic force acting on the wire, you can use the equation:
F = BIL sin(theta)
where F is the magnetic force, B is the magnetic field strength, I is the current in the wire, L is the length of the wire, and theta is the angle between the direction of the current and the direction of the magnetic field.
Given:
B = 1 × 10^-5 T (magnetic field strength)
I = 5.2 A (current in wire)
L = 6.0 m (length of wire)
theta = 90 degrees (since the current is perpendicular to the magnetic field)
First, convert theta from degrees to radians:
theta = 90 degrees * (pi/180 degrees) = pi/2 radians
Now, substitute the given values into the formula:
F = (1 × 10^-5 T)(5.2 A)(6.0 m) sin(pi/2)
Considering that sin(pi/2) = 1, simplify the equation:
F = (1 × 10^-5 T)(5.2 A)(6.0 m) = 3.1 × 10^-4 N
Therefore, the magnitude of the magnetic force acting on the wire is 3.1 × 10^-4 N.