Posted by **InDireNeedOfHelp** on Monday, June 9, 2014 at 10:46am.

You have five $1 bills, four $5 bills six $10 bills and three $20 bills. You select a bills at random. Without replacing the bill, You choose a second bill. What is P($1, then $10)?

- MATH -
**Elena**, Monday, June 9, 2014 at 11:01am
I think it's B. The probabilities change every time a bill is pulled out. The probability of pulling out a 1 first is 5 out of 18 which is .227 then the probability of pulling out a 10 is 6 out of 17 because you don't replace the bill. since the events are independent of each other, you get .35, then you multiply them to get .098 which in fraction form is answer B.

B. 5/51

## Answer this Question

## Related Questions

- MATH - You have five $1 bills, four $5 bills six $10 bills and three $20 bills. ...
- Math - You have six $1 bills, eight $5 bills, two $10 bills, and four $20 bills ...
- Math - You have six $1 bills, eight $5 bills, two $10 bills, and four$20 dollar ...
- math (please check answer) - 10. You have six $1 bills, eight $5 bills, two $10 ...
- probability - Assume that there is an urn containing seven $50 bills, six $20 ...
- statistics - I have 6 bills that total $63 and there are no $1 or coins? what ...
- math - Joseph sold tickets to the school musical. He had 12 bills worth $175 for...
- Algebra - I have 18 bills that equal $100.00 (5-$10 bills, 9-$5 bills, 3-$1 ...
- statistics - The customer bills in a family restaurant are normally distributed...
- Algebra - For a board game there is 3 kinds of bills. There are 11 more $2 bills...