math help plz2!!!!
posted by julissa on .
Find an equation of parabola that has the indicated vertex and whose graph passes through the given point.
Vertex (3,5)
Point (6,1)

****Point(6,1)

from the vertex, we know that
y = a(x+3)^2+5
Now plug in the values to get a:
1 = a(6+3)^2 + 5
9a = 4
a = 4/9
y = 4/9 (x+3)^2 + 5
See
http://www.wolframalpha.com/input/?i=y+%3D+4%2F9+%28x%2B3%29^2+%2B+5