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Posted by on Sunday, June 8, 2014 at 2:25pm.

the no. of real roots of eqn (x-1)POWER 2 + (X-2) POWER 2 +(X-3) POWER 2= 0 IS:

  • math - , Sunday, June 8, 2014 at 7:21pm

    lose all the nonsense text. You have

    (x-1)^2 + (x-2)^2 + (x-3)^2 = 0

    Now, you know that (x-1)^2 is a parabola, which is tangent to the x-axis at x=1, because of the double root.

    Similarly, the other two terms are never negative. So, since we are adding up three positive values for each x, the graph will never cross the x-axis, meaning there are no real roots.

    Or, try expanding things to get


    Since the discriminant is negative, there are no real roots.

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