Posted by **shish** on Sunday, June 8, 2014 at 2:25pm.

the no. of real roots of eqn (x-1)POWER 2 + (X-2) POWER 2 +(X-3) POWER 2= 0 IS:

- math -
**Steve**, Sunday, June 8, 2014 at 7:21pm
lose all the nonsense text. You have

(x-1)^2 + (x-2)^2 + (x-3)^2 = 0

Now, you know that (x-1)^2 is a parabola, which is tangent to the x-axis at x=1, because of the double root.

Similarly, the other two terms are never negative. So, since we are adding up three positive values for each x, the graph will never cross the x-axis, meaning there are no real roots.

Or, try expanding things to get

3x^2-12x+14=0

Since the discriminant is negative, there are no real roots.

## Answer This Question

## Related Questions

- mathematics - [{(3 to power 5by2*5 to power 3by4)/2to power -5by4}/{16/5 to ...
- math - find the greatest common factor and simplify your answer. 4v to the 7th ...
- physics - The disk shaped head of a pin is 1.0 mm in diameter. Which of the ...
- math - simplify, 4v to the 7th power y to the 9th power and 16v to the 6th power...
- math - 4v to the 7th power y to the 9th power and 16v to the 6th power x to the ...
- algebra - Please help I have tried this question so many times: I cannot type ...
- college - let i = the square root of -1 with i to the 1st power =i, i to the 2nd...
- 8th grade Math - I'm actually in 7th grade, but I'm doing 8th grade pre-algebra...
- math - List all possible rational zeros of... h(x)= 2x to the (4th power) - 5x (...
- MATH PLS HELP ME - What is 3 to the power of two thirds equal to? 3 to the power...

More Related Questions