Tuesday

March 31, 2015

March 31, 2015

Posted by **Veronica** on Sunday, June 8, 2014 at 11:22am.

2 H2S <--> 2 H2 + S2

I have come up with this equation so far, but I am lost now because I don’t even know if this is right.

1.67x10^-7 = ((4x^2)(x)) / (0.000625-4x^2)

- Chemistry -
**DrBob222**, Sunday, June 8, 2014 at 2:25pmIt's close but not right.

1.67E-7 = (2x)^2(x)/(0.025-2x)^2 is what you started with and that's correct. Your error was in expanding the denominator.

1.67E-7 = 4x^3/(6.25E-4 -0.1x +4x^2)

The next step is to multiply 1.67E-7 x the denominator, then collect the terms in descending order and you end up with a cubic equation. I haven't checked this but I ended up with (and you should go through the math to make sure it's right)

4x^3 -6.68E-7x^2 +1.67E-8x -1/04E-10 = 0

and solve that for x.

- oops--Chemistry -
**DrBob222**, Sunday, June 8, 2014 at 2:36pmI made a typo in that cubic equation.

4x^3-6.68E-7x^2+1.67E-8x-1.04E-10 = 0

**Answer this Question**

**Related Questions**

Chemistry - A 0.500L vessel initially contains 0.0125 mol of H2S2 . Find the ...

Chemistry - When CH4(g) (0.06318 mol/L) and 16.43 mol of H2S(g) in a 130.0 L ...

AP CHEM - I would really appreciate some help on this problem. =) At 218 C, Kc...

AP CHEMISTRY - A mixture of H2, S, and H2S is held in a 1.0-L vessel at 90°C and...

chemistry - If 1.00 mol of iodine and 0.50 mol of chlorine are initially placed ...

chemistry - If 0.50 mol of iodine and 0.50 mols of chlorine are initially placed...

Chemistry - X2 + Y2 <=> 2XY 0.50 mole each of X2 and Y2 are placed in a 1....

equilbrium II - when CO2 (.15mol) and H2 (.302g) in a 500L vessel at 576'C are ...

Chemistry - Consider the equilibrium 2NOCl (g) <---> 2NO (g) + Cl2 (g). In...

Chemistry - At a particular temperature, K = 2.0 10-6 mol/L for the following ...