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November 21, 2014

November 21, 2014

Posted by **susan** on Sunday, June 8, 2014 at 11:12am.

1x10*-14/-80=-log(answer)

How would I do this since I can not take the negative log of the previous anwser

- chemistry -
**DrBob222**, Sunday, June 8, 2014 at 3:15pmI can tell you how to do it if you can tell me how you get a concn of anything less than zero. I can see (OH^-) = 1 x 10^-80 but that is still more than zero. Not by much I'll grant you, but still more than zero.

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