Sunday

January 25, 2015

January 25, 2015

Posted by **amit** on Sunday, June 8, 2014 at 3:35am.

- math -
**Reiny**, Sunday, June 8, 2014 at 8:17amlet a^(2/3) = y for easier typing

then x = y - 1/y

= (y^2 - 1)/y

x^3 = (y^6 -3y^4 + 3y^2 - 1) / y^3

= (a^4 - 3a^(8/3) + 3a^(4/3) - 1)/a^2

or

a^2 - 3a^(2/3) + 3a^(-2/3) - a^-2

3x = 3a^(2/3) - 3a^(-2/3)

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