Posted by **Me** on Sunday, June 8, 2014 at 3:11am.

A train on a mountain railway is carrying 200 people of average mass 70kg up a slope at an angle of 30° to the horizontal and at a speed of 6.0 m s–1. The train itself has a mass of 80 000 kg. The percentage of the power from the engine which is used to raise the passengers and the train is 40%.

What is the power of the engine?

- Physics -
**MathMate**, Sunday, June 8, 2014 at 6:34am
Power=Mg(speed)*sin(θ)/0.40 watts

M=total mass (passengers, train, etc.)

- Physics -
**Anonymous**, Wednesday, November 26, 2014 at 12:00pm
mass of passengers=200*70=14000...total mass of train +passengers=80000+14000... their weight =94000*9.81=922140..now force = mgsin30= 922140sin30=461070.. power =force*velocity= 461070*6=2766420..this is power output.. now we know that power output divide by power input *100%=40%..solve it to get the answer 6.9MW...

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