Chemistry
posted by Veronica .
A 0.500L vessel initially contains 0.0125 mol of H2S2 . Find the equilibrium concentrations of H2 and S2. Kc = 1.67 x 10^7
2 H2S <> 2 H2 + S2

M H2S2 initially = 0.0125/0.5 = 0.025M
............2H2S ==> 2H2 + S2
I...........0.025.....0.....0
C............2x......2x.....x
E.........0.0252x....2x.....x
Substitute the E line into the Kc expression and solve for x. 
I got this equation but now I am lost
1.67x10^7 = ((4x^2)(x)) / (0.0006254x^2)