Posted by **Veronica** on Saturday, June 7, 2014 at 9:49pm.

A 0.500L vessel initially contains 0.0125 mol of H2S2 . Find the equilibrium concentrations of H2 and S2. Kc = 1.67 x 10^-7

2 H2S <--> 2 H2 + S2

- Chemistry -
**DrBob222**, Saturday, June 7, 2014 at 11:13pm
M H2S2 initially = 0.0125/0.5 = 0.025M

............2H2S ==> 2H2 + S2

I...........0.025.....0.....0

C............-2x......2x.....x

E.........0.025-2x....2x.....x

Substitute the E line into the Kc expression and solve for x.

- Chemistry -
**Veronica**, Sunday, June 8, 2014 at 10:42am
I got this equation but now I am lost

1.67x10^-7 = ((4x^2)(x)) / (0.000625-4x^2)

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