Posted by **Tiffany** on Saturday, June 7, 2014 at 8:04pm.

1+2+3+...+n=(1+n)+(2+(n-1))+(3+(n-2))+...

=(1+n)+(1+n)+(1+n)+...

How many copies of n+1 are in there in the second line?

with n=6 and n=7

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