Conjure a visual representation of a mathematical progression denoted by the arithmetic progression formula, in a minimalist style. Depict the sequence in a flowing manner starting with smaller circles symbolizing the initial terms and gradually increasing to larger circles symbolizing the later terms. Make sure to emphasize the terms 11, 28 and 45 through distinct coloration or size. Display the common difference of 45 as visual spacing between the circles. Do not include any text in the image.

the sum of 11terms of A.P is 891.find the 28th and 45th terms if the common difference is 45

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abcd is atrape zium in whibh ab 11 dc.\ab/=4 11cm.\dc/=9cm abc =68,\bb/=7.5cm calculate the area of the trapezium?

To find the 28th and 45th terms of an arithmetic progression (A.P) with a common difference of 45, we first need to find the first term (a) and the common difference (d). Given that the sum of the first 11 terms is 891, we can use this information to find a.

The sum of the first n terms of an A.P is given by the formula: Sn = (n/2)(2a + (n-1)d)

Substituting the given values, we have:
891 = (11/2)(2a + (11-1)(45))
891 = (11/2)(2a + 10(45))
891 = (11/2)(2a + 450)
891 = 11a + 495
11a = 891 - 495
11a = 396
a = 396/11
a = 36

Now that we know the first term (a = 36) and the common difference (d = 45), we can find the 28th and 45th terms.

The general formula to find the nth term of an A.P is: An = a + (n - 1)d

For the 28th term:
A28 = 36 + (28 - 1)(45)
A28 = 36 + 27(45)
A28 = 36 + 1215
A28 = 1251

For the 45th term:
A45 = 36 + (45 - 1)(45)
A45 = 36 + 44(45)
A45 = 36 + 1980
A45 = 2016

Therefore, the 28th term is 1251 and the 45th term is 2016.

the sum of 11 terms of an a.p is 891 find the 28th and 45th terms if the common difference is 15

I need an accurate answer toward the question

The sum of 11 terms of an Ap is 891,find the 28th and 45th terms if the common difference is 15

If we add up terms n through n+10, then we get

(n+10)/2 (2a + (n+9)45) - (n-1)/2 (2a+(n-2)45) = 891
11a+495n = -1089
a+45n = -99

If we are adding up the first 11 terms, then a = -144 and
T28 = -144+27*45 = 1071
T45 = -144+44*45 = 1836

But, if we add up terms T5 through T15, then n=5, and a = -324 and
T28 = 891
T45 = 1656

Better tie down your conditions a bit better