a pole 10m long rests slantly against a vertical wall ab making 60 degrees with the horizontal (ground). find how faris the foot of the pole from the wall

10 cos(60°)

There is no answer

To find the distance of the foot of the pole from the wall, we can use trigonometry. Let's break down the problem step by step:

Step 1: Draw a diagram:
Draw a right-angled triangle where the pole is the hypotenuse, the wall is the vertical side (height), and the distance from the foot of the pole to the wall is the horizontal side (base).

|
|\
| \
| \
ab \
| \
| \
|_ \
|_ _\_
10m

Step 2: Identify the given values:
We are given that the pole is 10 meters long and makes a 60-degree angle with the horizontal ground.

Step 3: Identify the trigonometric function to use:
Since we know the length of the hypotenuse (10m) and want to find the length of the base, we can use the cosine function, which relates the adjacent side (base) to the hypotenuse.

Step 4: Apply the cosine function:
cos(angle) = adjacent/hypotenuse
cos(60 degrees) = base/10m

Step 5: Solve for the base:
base = cos(60 degrees) * 10m

Now, let's calculate the distance of the foot of the pole from the wall:

base = cos(60 degrees) * 10m
base = 0.5 * 10m
base = 5m

Therefore, the foot of the pole is 5 meters away from the wall.