A kite is flying at an angle of elevation of 40 degrees. All 80 m of string have been let out. Ignoring the sag in the string, the height of the kite to the nearest 10 m is __?__ meters.

sin 40° = x/80

To find the height of the kite, we can use trigonometry. The angle of elevation (40 degrees) forms a right triangle with the height of the kite as one side and the string as the hypotenuse.

Using the sine function, we can solve for the height of the kite (h):

sin(40°) = h / 80

To find h, we can rearrange the equation:

h = 80 * sin(40°)

Using a calculator, we can find the sine of 40 degrees:

sin(40°) ≈ 0.6428

Now, we substitute this value back into the equation:

h = 80 * 0.6428

h ≈ 51.43

Therefore, the height of the kite to the nearest 10 m is 50 m.

To find the height of the kite, we can use trigonometry. In this case, we can use the tangent function.

The tangent of an angle is equal to the opposite side divided by the adjacent side. In this scenario, the height of the kite is the opposite side, and the length of the string is the adjacent side.

Given that the angle of elevation is 40 degrees and the length of the string is 80 meters, we can set up the equation:

tan(40 degrees) = height / 80

To solve for the height, we can rearrange the equation:

height = tan(40 degrees) * 80

Using a calculator, we can find the tangent of 40 degrees and multiply it by 80 to get the height of the kite. Rounding the answer to the nearest 10 meters, the height of the kite is approximately __?__ meters.