One 10.0 Ω resistor is wired in series with 10.0 Ω resistors in parallel. A 45.0 V battery supplies power to the circuit. What is the total current through the circuit?
A. 3.0 A
B. 1.5 A
C. 0.75 A
D. 0.33 A
Do you mean
one 10Ω is in series with two 10Ω in parallel?
the ones in parallel are worth 5Ω so the total equivalent resistance is 10+5=15.
Use V=IR
thx, i did not know that, so the answer is D :)
V/R = i = 45/15 = 3 amps
ohh oops, i did 15/45, thank you, Damon
You are welcome.
To find the total current through the circuit, you can use Ohm's Law and the concept of equivalent resistance.
First, calculate the equivalent resistance (Req) of the resistors wired in parallel. When resistors are in parallel, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances.
For two 10.0 Ω resistors in parallel:
1/Req = 1/R1 + 1/R2
1/Req = 1/10 + 1/10
1/Req = 2/10
1/Req = 1/5
Req = 5 Ω
Now that you have the equivalent resistance of the parallel resistors, you can calculate the total current (Itotal) using Ohm's Law:
Itotal = V / Req
Itotal = 45 V / 5 Ω
Itotal = 9 A
Therefore, the correct answer is not provided in the given options.