The probability of a CD case being defective is 1/520. If the factory makes 7,800 cases per week, how many are likely to be defective?
I don't understand this its so confusing :(
Is it 7,800 divided by 520?
yes, but I would rather have you think of
(1/520)(7800)
= 7800/520 ---> see, there is your division by 520
= 15
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<3<3 Reiny
I was on this question for so long!
I can help break down the problem for you step by step. To find the number of CD cases likely to be defective, you'll need to use the concept of probability and a little bit of math.
Step 1: Calculate the probability of a CD case being defective.
The problem states that the probability of a CD case being defective is 1/520. This means that out of every 520 CD cases produced, only 1 is likely to be defective.
Step 2: Calculate the number of CD cases produced per week.
The problem states that the factory makes 7,800 cases per week.
Step 3: Determine the number of defective CD cases.
To calculate the number of defective cases, we need to multiply the probability and the number of cases produced per week.
Number of defective CD cases = Probability of defectiveness x Number of cases produced per week
Number of defective CD cases = (1/520) x 7,800
Step 4: Simplify the equation.
To simplify the equation, we can divide both the numerator and denominator by the greatest common divisor (GCD) of 1 and 520, which is 1.
Number of defective CD cases = (1/520) x 7,800
Number of defective CD cases = 7,800/520
Number of defective CD cases = 15
Therefore, based on the given probability and the number of CD cases produced per week, it is likely that 15 CD cases will be defective.