n(n-1)-4
How do I solve stuff like this?
How would I also solve the following?
f(x)=x^2-4+3 what is the output of f(-3)?
Just use the distributive property:
n(n-1)-4
n*n - n*1 - 4
n^2-n-4
Since f(x) = x^2-4x+3, and you want f(-3), just replace all the x's with -3 and you have
f(-3) = (-3)^2 - 4(-3) + 3
= 9+12+3
= 24
To solve the expression n(n-1)-4, you can follow these steps:
Step 1: Expand the expression by multiplying n with both (n-1) terms:
n(n-1)-4 = n^2 - n - 4
Step 2: Simplify the expression if possible. In this case, the expression cannot be further simplified.
Now you have the simplified expression: n^2 - n - 4. This is the solution to the given expression.
If you need to solve for a specific value, you can substitute a value for n and evaluate the expression. For example, if you want to find the result for n = 2, substitute it into the expression:
n^2 - n - 4
= (2)^2 - (2) - 4
= 4 - 2 - 4
= -2
So, when n is 2, the expression evaluates to -2.