if a population comprised 52 AA, 114 Aa and 34 aa individuals and the 'A' allele was dominant, what would be the genotype, allele, and phenotype frequencies be
Who is mating with whom? For example AA with AA, all offspring would be AA.
To determine the genotype, allele, and phenotype frequencies in this population, we need to calculate the number of individuals with each genotype and allele.
Given the following counts:
- 52 individuals with the AA genotype
- 114 individuals with the Aa genotype
- 34 individuals with the aa genotype
Genotype frequencies can be calculated by dividing the count of individuals with a specific genotype by the total population size.
The total population size is obtained by adding the counts from all three genotypes: 52 + 114 + 34 = 200.
Genotype frequencies:
- AA: 52 / 200 = 0.26 or 26%
- Aa: 114 / 200 = 0.57 or 57%
- aa: 34 / 200 = 0.17 or 17%
To calculate allele frequencies, we need to consider that the AA genotype has two copies of the 'A' allele, the Aa genotype has one 'A' allele, and the aa genotype has two copies of the 'a' allele.
Since each individual has two alleles, the total number of alleles in the population is 2 * the total population size: 2 * 200 = 400.
Allele frequencies:
- 'A' allele: (2 * 52 + 114) / 400 = 0.445 or 44.5%
- 'a' allele: (2 * 34 + 114) / 400 = 0.555 or 55.5%
Finally, to determine the phenotype frequencies, we consider the expression of the dominant 'A' allele, which results in the AA and Aa genotypes having the same phenotype.
Phenotype frequencies:
- Dominant phenotype: AA + Aa = 52 + 114 = 166 individuals -> 166 / 200 = 0.83 or 83%
- Recessive phenotype: aa = 34 individuals -> 34 / 200 = 0.17 or 17%
In summary:
Genotype frequencies:
- AA: 0.26 (26%)
- Aa: 0.57 (57%)
- aa: 0.17 (17%)
Allele frequencies:
- 'A' allele: 0.445 (44.5%)
- 'a' allele: 0.555 (55.5%)
Phenotype frequencies:
- Dominant phenotype: 0.83 (83%)
- Recessive phenotype: 0.17 (17%)