In how many ways can 6 toy animals be arranged in a line on a shelf if one of the toys is a tortoise and it must be at the end of the line?
if the tortoise is last, then you just have to worry about the other 5 animals.
So, in how many ways can you arrange 5 things?
Let's be rational
In how many ways can 6 toy animals be arranged in a line on a shelf if one of the toys is a tortoise and it must be at the end of the line?
To calculate the number of ways that 6 toy animals can be arranged in a line with a tortoise at the end, we can use the factorial function.
Factorial: The factorial of a number n, denoted as n!, is the product of all positive integers from 1 to n. For example, 4! = 4 × 3 × 2 × 1 = 24.
In this case, we have 5 toys (excluding the tortoise) that need to be arranged. The number of ways to arrange these 5 toys can be calculated as 5! = 5 × 4 × 3 × 2 × 1 = 120.
Therefore, there are 120 different ways to arrange the 6 toy animals in a line with the tortoise at the end.