Post a New Question


posted by .

An aircraft which is maintaining a constant altitude of 1000 meters is travelling directly away from an observer. At a particular instant the sngle of elevation is 52 degrees and 12 seconds later the angle of elevation is 16 degrees. Find the distance travelled in this time.
(Use sine rule)


  • Math -

    Hmmm. I don't see an obvious application of the law of sines here. However, if we consider the distance directly to the plane, and call the first one x and the second one y, then

    1000/x = sin52°
    1000/y = sin16°
    Then we want the distance z given by the law of cosines,
    z^2 = x^2+y^2-2xy cos(52-16)°


    z/sin36° = x/sin16° = y/sin128°

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question